document.write( "Question 838352: At 10:00 am. a car leaves a house at a rate of 60mph. At the same time, another car leaves the same house at a rate of 50mph in the opposite direction. At what clock time will the cars be 330 miles apart?\r
\n" ); document.write( "\n" ); document.write( "I tried using a graph my teacher gave us to solve these, but I am so lost. I have absolutely no idea how to do this problem. Help will be much appreciated. Thank you!
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Algebra.Com's Answer #505019 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Their speeds will add since they are going
\n" ); document.write( "in opposite directions
\n" ); document.write( "You can think of one car ( either car ) as
\n" ); document.write( "standing still and the other one moving
\n" ); document.write( "away at the sum of their speeds
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\n" ); document.write( "The sum of the speeds is:
\n" ); document.write( "\"+60+%2B+50+=+110+\" mi/hr
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\n" ); document.write( "Let \"+t+\" = the time in hours that elapses
\n" ); document.write( "until they are \"+330+\" miles apart
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\n" ); document.write( "Now I can say:
\n" ); document.write( "\"+330+=+110t+\"
\n" ); document.write( "\"+t+=+3+\" hrs
\n" ); document.write( "\"+3+\" hrs after 10 AM is 1 PM
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\n" ); document.write( "You can check this method by saying
\n" ); document.write( "\"+d%5B1%5D+\" is the distance the faster car goes in \"+3+\" hrs
\n" ); document.write( "\"+d%5B2%5D+\" is the distance the slower car goes in \"+3+\" hrs
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\n" ); document.write( "\"+d%5B1%5D+=+60%2A3+\"
\n" ); document.write( "\"+d%5B1%5D+=+180+\" mi
\n" ); document.write( "and
\n" ); document.write( "\"+d%5B2%5D+=+50%2A3+\"
\n" ); document.write( "\"+d%5B2%5D+=+150+\" mi
\n" ); document.write( "and
\n" ); document.write( "\"+d%5B1%5D+%2B+d%5B2%5D+=+180+%2B+150+\"
\n" ); document.write( "\"+d%5B1%5D+%2B+d%5B2%5D+=+330+\" mi
\n" ); document.write( "as it should- OK
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