document.write( "Question 838327: A jazz group on tour has been drawing average crowds of 600 people. It is projected that for every $1 increase in the $12 ticket price, the average attendance will decrease by 75. At what ticket price will nightly receipts be $6,300? \n" ); document.write( "

Algebra.Com's Answer #505006 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+n+\"$ = the number of $1 increases in ticket price:
\n" ); document.write( " $\"+75n+\"$ = the increase in attendance for $\"+n+\"$ $1
\n" ); document.write( "increases in ticket price
\n" ); document.write( "------------------------
\n" ); document.write( " $\"+6300+=+%28+12+%2B+1%2An+%29%2A%28+600+-+75n+%29+\"$
\n" ); document.write( "-----------------------------------
\n" ); document.write( " $\"+6300+=+12%2A600+%2B+600n+-+12%2A75%2An+-+75n%5E2+\"$
\n" ); document.write( " $\"+75n%5E2+%2B+300n+-+900+=+0+\"$
\n" ); document.write( " $\"+n%5E2+%2B+4n+-+12+=+0+\"$
\n" ); document.write( " $\"+%28+n+-+2+%29%2A%28+n+%2B+6+%29+=+0+\"$ ( I just guessed at this )
\n" ); document.write( " $\"+n+=+2+\"$ is the answer since $\"+n+=+-6+\"$ won't work
\n" ); document.write( "Plugging this back in:
\n" ); document.write( " $\"+6300+=+%28+12+%2B+1%2An+%29%2A%28+600+-+75n+%29+\"$
\n" ); document.write( " $\"+6300+=+%28+12+%2B+1%2A2+%29%2A%28+600+-+75%2A2+%29+\"$
\n" ); document.write( " $\"+6300+=+14%2A450+\"$
\n" ); document.write( " $\"+6300+=+6300+\"$
\n" ); document.write( "The nightly ticket price is $\"+12+%2B+2+\"$ = $14
\n" ); document.write( " \n" ); document.write( "

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