document.write( "Question 838177: In a 1000m race, Jacqui finishes 100m ahead of Lisa and 190 m in front of Fran. If Lisa and Fran continue to run at the same speed how far in front of Fran will Lisa finish \n" ); document.write( "
Algebra.Com's Answer #504990 by ankor@dixie-net.com(22740)\"\" \"About 
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In a 1000m race, Jacqui finishes 100m ahead of Lisa and 190 m in front of Fran.
\n" ); document.write( " If Lisa and Fran continue to run at the same speed, how far in front of Fran will Lisa finish.
\n" ); document.write( ":
\n" ); document.write( "Let's assume J runs the race in 100 sec
\n" ); document.write( "then
\n" ); document.write( "\"1000%2F100\" = 10 m/sec is J's speed
\n" ); document.write( ":
\n" ); document.write( "L ran 900 m in 100 sec, therefore
\n" ); document.write( "\"900%2F1000\" = 9 m/sec is L's speed
\n" ); document.write( "and
\n" ); document.write( "F ran 810 m in 100 sec
\n" ); document.write( "\"810%2F100\" = 8.1 m/sec is F's speed
\n" ); document.write( ":
\n" ); document.write( "Find how long it takes L to go 1000m at 9 m/sec
\n" ); document.write( "\"1000%2F9\" = 111.1 sec
\n" ); document.write( "Find how far F travels in 111.1 sec
\n" ); document.write( "111.1 * 8.1 = 900 meters
\n" ); document.write( "therefore
\n" ); document.write( "L will be 100 meters ahead of F, when she finishes
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