document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=838133>Question 838133</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many 3 digit integers greater than 499 have exactly two repeated digits </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #504970 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=504970\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For the 500s there are 500, 511, ..., 599 as well as 550, 551, 552, ..., 559 giving us 10+10 = 20 numbers. However we are counting 555 twice, but we want to count it zero times, so we subtract 555 twice, giving us 18 numbers between 500 and 599 (inclusive) with two repeated digits.\r<BR>\n" );
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document.write( "Same thing holds for 600-699, ..., 900-999, giving us 18*5 = 90 numbers. </SPAN>\n" );
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