document.write( "Question 838201: if m is an integer such that 〖(-2)〗^2m =2^(9-m), then m=? \n" ); document.write( "

Algebra.Com's Answer #504969 by LinnW(1048) $\"\"$ $\"About$

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If the exponents are even,
\n" ); document.write( "(-2)^(2m) = 2^(9-m) is
\n" ); document.write( "the same as
\n" ); document.write( "2^(2m) = 2^(9-m) and
\n" ); document.write( "2m = 9-m
\n" ); document.write( "add m to each side
\n" ); document.write( "3m = 9
\n" ); document.write( "m = 3
\n" ); document.write( "plugging 3 for m in the original equation
\n" ); document.write( "(-2)^(2m) = 2^(9-m) becomes
\n" ); document.write( "(-2)^(2*3) ?= 2^(9-3)
\n" ); document.write( "(-2)^(6) ?= 2^(6)
\n" ); document.write( "2^6 = 2^6
\n" ); document.write( "So m = 3 is the solution. \n" ); document.write( "

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