document.write( "Question 838100: Mardi received an inheritance of $50,000. She invested part at 1.75% and deposited the remainder in tax-free bonds at 2%. Her total annual income from the investments was $900. Find the amount invested at 1.75%\r
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Algebra.Com's Answer #504874 by mananth(16946)\"\" \"About 
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Part I 1.75% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 2.00% per annum ------------ Amount invested = y
\n" ); document.write( " 50000
\n" ); document.write( "Interest----- 900.00
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\n" ); document.write( "Part I 1.75% per annum ---x
\n" ); document.write( "Part II 2.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 50000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "1.75% x + 2.00% y= 900
\n" ); document.write( "Multiply by 100
\n" ); document.write( "1.75 x + 2 y= 90000.00 --------2
\n" ); document.write( "Multiply (1) by -1.75
\n" ); document.write( "we get
\n" ); document.write( "-1.75 x -1.75 y= -87500.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x 0.25 y= 2500
\n" ); document.write( "divide by 0.25
\n" ); document.write( " y = 10000
\n" ); document.write( "Part I 1.75% $ 40000
\n" ); document.write( "Part II 2.00% $ 10000
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\n" ); document.write( "CHECK
\n" ); document.write( "40000 --------- 1.75% ------- 700.00
\n" ); document.write( "10000 ------------- 2.00% ------- 200.00
\n" ); document.write( "Total -------------------- 900.00
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\n" ); document.write( "m.ananth@hotmail.ca
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