document.write( "Question 838146: A 20 foot ladder is placed against a building in such a way that the distance from the top of the ladder to the ground is 4 feet more than the distance from the bottom of the ladder to the wall. Find the distance from the bottom of the ladder to the wall. \n" ); document.write( "
Algebra.Com's Answer #504873 by mananth(16946)![]() ![]() You can put this solution on YOUR website! distance from wall to the foot of ladder be x \n" ); document.write( "The distance from top of ladder to the ground=(x+4) \n" ); document.write( "Ladder length = 20 feet\r \n" ); document.write( "\n" ); document.write( "The ground wall and ladder form a right triangle\r \n" ); document.write( "\n" ); document.write( "apply Pythagoras theorem\r \n" ); document.write( "\n" ); document.write( "x^2+(x+4)^2=20^2\r \n" ); document.write( "\n" ); document.write( "x^2+x^2+8x+16=400\r \n" ); document.write( "\n" ); document.write( "2x^2+8x-400+16=0 \n" ); document.write( "2x^2+8x-384=0 \n" ); document.write( "/2 \n" ); document.write( "x^2+4x-192=0 \n" ); document.write( "complete the squares\r \n" ); document.write( "\n" ); document.write( "x^2+4x+4-4-192=0\r \n" ); document.write( "\n" ); document.write( "(x+2)^2= 196\r \n" ); document.write( "\n" ); document.write( "take the positive square root\r \n" ); document.write( "\n" ); document.write( "x+2=13 \n" ); document.write( "x=11\r \n" ); document.write( "\n" ); document.write( "(x+2)=13\r \n" ); document.write( "\n" ); document.write( "distance from wall to the foot of ladder 11 feet \n" ); document.write( "The distance from top of ladder to the ground=13 feet\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |