document.write( "Question 838146: A 20 foot ladder is placed against a building in such a way that the distance from the top of the ladder to the ground is 4 feet more than the distance from the bottom of the ladder to the wall. Find the distance from the bottom of the ladder to the wall. \n" ); document.write( "
Algebra.Com's Answer #504873 by mananth(16946)\"\" \"About 
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distance from wall to the foot of ladder be x
\n" ); document.write( "The distance from top of ladder to the ground=(x+4)
\n" ); document.write( "Ladder length = 20 feet\r
\n" ); document.write( "\n" ); document.write( "The ground wall and ladder form a right triangle\r
\n" ); document.write( "\n" ); document.write( "apply Pythagoras theorem\r
\n" ); document.write( "\n" ); document.write( "x^2+(x+4)^2=20^2\r
\n" ); document.write( "\n" ); document.write( "x^2+x^2+8x+16=400\r
\n" ); document.write( "\n" ); document.write( "2x^2+8x-400+16=0
\n" ); document.write( "2x^2+8x-384=0
\n" ); document.write( "/2
\n" ); document.write( "x^2+4x-192=0
\n" ); document.write( "complete the squares\r
\n" ); document.write( "\n" ); document.write( "x^2+4x+4-4-192=0\r
\n" ); document.write( "\n" ); document.write( "(x+2)^2= 196\r
\n" ); document.write( "\n" ); document.write( "take the positive square root\r
\n" ); document.write( "\n" ); document.write( "x+2=13
\n" ); document.write( "x=11\r
\n" ); document.write( "\n" ); document.write( "(x+2)=13\r
\n" ); document.write( "\n" ); document.write( "distance from wall to the foot of ladder 11 feet
\n" ); document.write( "The distance from top of ladder to the ground=13 feet\r
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