document.write( "Question 838127: A company invested $32,000, putting part of it into a savings account that earned 3.9% annual simple interest and the remainder in a stock fund that earned 12.9% annual simple interest. If the investments earned $1878 annually, how much was in each account?
\n" ); document.write( "savings account:
\n" ); document.write( "stock fund: \n" ); document.write( "
Algebra.Com's Answer #504871 by mananth(16946)\"\" \"About 
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Part I 3.90% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 12.90% per annum ------------ Amount invested = y
\n" ); document.write( " 32000
\n" ); document.write( "Interest----- 1878.00
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\n" ); document.write( "Part I 3.90% per annum ---x
\n" ); document.write( "Part II 12.90% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 32000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "3.90% x + 12.90% y= 1878
\n" ); document.write( "Multiply by 100
\n" ); document.write( "3.9 x + 12.9 y= 187800.00 --------2
\n" ); document.write( "Multiply (1) by -3.9
\n" ); document.write( "we get
\n" ); document.write( "-3.9 x -3.9 y= -124800.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x 9 y= 63000
\n" ); document.write( "divide by 9
\n" ); document.write( " y = 7000
\n" ); document.write( "Part I 3.90% $ 25000
\n" ); document.write( "Part II 12.90% $ 7000
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\n" ); document.write( "CHECK
\n" ); document.write( "25000 --------- 3.90% ------- 975.00
\n" ); document.write( "7000 ------------- 12.90% ------- 903.00
\n" ); document.write( "Total -------------------- 1878.00
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\n" ); document.write( "m.ananth@hotmail.ca
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