document.write( "Question 838116: Twenty five men have enough food for 100 days. twenty days later five more men arrive at the camp.how long will the remaining food last for now? \n" ); document.write( "

Algebra.Com's Answer #504867 by josgarithmetic(39625) $\"\"$ $\"About$

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This is a task rates problem, a kind of uniform rates situation.\r
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\n" ); document.write( "\n" ); document.write( "The task to be done is, \"consume the food\". We do not know the amount of food, but we just know the rate at which 25 men will consume it, and the number of days that way.\r
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\n" ); document.write( "\n" ); document.write( "Find the rate of one man. One man will need 25 times more days than will 25 men.\r
\n" ); document.write( "\n" ); document.write( "Follow that and say, 1 man needs $\"25%2A100\"$ days to consume the supply of food.
\n" ); document.write( "This is 1 task per 2500 days, or $\"1%2F2500\"$ jobs per day, the one-man rate.\r
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\n" ); document.write( "\n" ); document.write( "Now you have 25 men consuming for 20 days, and then you have 25+5 men consuming food for unknown d number of days. We want to find d. We have the sum of two portions of the task:\r
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\n" ); document.write( "\n" ); document.write( " $\"highlight%2825%281%2F2500%29%2A20%2B30%281%2F2500%29d=1%29\"$ , one whole task of consuming the supply of food. This is $\"Rate1%2ATime1%2BRate2%2ATime2=WholeTask\"$ , and is based on the uniform rate fact of $\"R%2At=j\"$ , where R is rate in job per time, and j is how much or many job.\r
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\n" ); document.write( "\n" ); document.write( "When you follow that description, then you are ready to solve for d. Number of days \"how long the food lasts\" once the 5 new men arrive. \n" ); document.write( "

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