document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=837762>Question 837762</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many liters each of a 75% chlorine solution and a 45% chlorine solution should be used to obtain 15 liters of a 65% chlorine solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #504853 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=504853\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How many liters each of a 75% chlorine solution and a 45% chlorine solution should be used to obtain 15 liters of a 65% chlorine solution?<BR>\n" );
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document.write( "Let x = amt of 75% solution<BR>\n" );
document.write( "then<BR>\n" );
document.write( "(15-x) = amt of 45% solution<BR>\n" );
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document.write( ".75x + .45(15-x) = .65(15)<BR>\n" );
document.write( ".75x + 6.75 - .45x = 9.75<BR>\n" );
document.write( ".75x - .45x = 9.75 - 6.75<BR>\n" );
document.write( "You should be able to complete this now, check solution in the original equation </SPAN>\n" );
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