document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=70726>Question 70726</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1. Find three consecutive numbers such that the sum of one-fourth the first and one-fifth the second is five less that one-seventh the third.\r<BR>\n" );
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document.write( "1/4n + 1/5n = (1/7n-5)\r<BR>\n" );
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document.write( "2.  The present ages of a husband and wife are in the ratio of seven to six and five years ago the ratio was six to five.  Find their ages now.\r<BR>\n" );
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document.write( "7/6=35/30 and 6/5=30/25 + 5/5=35/30\r<BR>\n" );
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document.write( "Husband is now 35 and wife is now 30.\r<BR>\n" );
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document.write( "3. An automobile's radiator has a capacity of fifteen quarters, and it currently contains twelve quarts of  thirty per cent antifreeze solution.\r<BR>\n" );
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document.write( "    a.  How many quarts of pure antifreeze must be added to strengthen the solution to forty per cent?\r<BR>\n" );
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document.write( "    b.  If the radiator is filled to capacity with pure anti-freeze, what will be the strength (per cent ) of this solution?\r<BR>\n" );
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document.write( "30% of 12 = 30/100 x 12 = 360/100 = 3.6\r<BR>\n" );
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document.write( "     a.  40% of 3.6 = 40/100 x 3.6 = 144\r<BR>\n" );
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document.write( "     b.  40% of 15 = 40/100 x 15 = 600\r<BR>\n" );
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document.write( "4.  Simplify the complex fraction n/3 - 3/n divided by 1 + n/3.\r<BR>\n" );
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document.write( "    solve:  ans. -3/n\r<BR>\n" );
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document.write( "Please help with these four problems.  Thank you very much.  It is urgent!\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50485 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50485\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THE THREE CONSECUTINE NUMBERS ARE X, (X+1), (X+2)<BR>\n" );
document.write( "X/4+(X+1)/5=(X+2)/7-5 FIND A COMMON DENOMINATOR<BR>\n" );
document.write( "(5X+4[X+1])/20=(X+2)/7-35/7<BR>\n" );
document.write( "(5X+4X+4)/20=(X-33)/7<BR>\n" );
document.write( "(9X+4)/20=(X-33)/7 NOW CROSS MULTIPLY<BR>\n" );
document.write( "20(X-33)=7(9X+4)<BR>\n" );
document.write( "20X-660=63X+28<BR>\n" );
document.write( "20X-63X=28+660<BR>\n" );
document.write( "-43X=688<BR>\n" );
document.write( "X=688/-43<BR>\n" );
document.write( "X=-16 ANSWER<BR>\n" );
document.write( "X+1=-15 ANSWER<BR>\n" );
document.write( "X=2=-14 ANSWER<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "-16/4+-15/5=-14/7-5<BR>\n" );
document.write( "-4-3=-2-5<BR>\n" );
document.write( "-7=-7\r<BR>\n" );
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