document.write( "Question 837999: Carrots sell for $2.10 per pound, and crackers sell for $2.90 per pound. Glen bought some carrots and some crackers. The total weight was 2.3 pounds and cost $6.03.\r
\n" ); document.write( "\n" ); document.write( "Let p represent the number of pounds of carrots. \r
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\n" ); document.write( "\n" ); document.write( "Which equation represents the situation described?
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Algebra.Com's Answer #504836 by josgarithmetic(39628)\"\" \"About 
You can put this solution on YOUR website!
List the facts and the variables.\r
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\n" ); document.write( "\n" ); document.write( "x is pounds of carrots
\n" ); document.write( "y is pounds of crackers
\n" ); document.write( "Carrot price, 2.10 dollars/pound
\n" ); document.write( "Crackers price, 2.90 dollars/pound
\n" ); document.write( "x+y=2.3 pounds of both items combined
\n" ); document.write( "Cost of both items, 6.03 dollars\r
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\n" ); document.write( "\n" ); document.write( "Account for pounds of the combined items, done already from the description: \"x%2By=2.3\"\r
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\n" ); document.write( "\n" ); document.write( "Account for the cost: \"2.1x%2B2.9y=6.03\"\r
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\n" ); document.write( "\n" ); document.write( "Substitution would be a good method.
\n" ); document.write( "y=2.3-x;
\n" ); document.write( "\"2.1x%2B2.9%282.3-x%29=6.03\"
\n" ); document.write( "\"2.1x%2B6.67-2.9x=6.03\"
\n" ); document.write( "\"-0.8x=6.03-6.67\"
\n" ); document.write( "\"0.8x=6.67-6.03=0.64\"
\n" ); document.write( "\"x=0.64%2F0.8\"-------Simplify this, and then use it to find y.
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