document.write( "Question 837990: N = 2/9P + 1
\n" ); document.write( "Solve for P
\n" ); document.write( "

Algebra.Com's Answer #504816 by josh_jordan(263)\"\" \"About 
You can put this solution on YOUR website!
I cannot tell if the P belongs in the denominator or if P is being multiplied by the entire fraction, so I will solve this based on both scenarios.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If the P is part of the denominator, solving for P will go as follows:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "1. Subtract 1 from both sides of the equation:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "N - 1 = 2/9P + 1 - 1 -----> N - 1 = 2/9P\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "2. Multiply both sides of the equation by 9P -----> \"9P%28N-1%29=2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "3. Divide both sides of the equation by 9(N - 1) -----> \"P=2%2F%289%28N-1%29%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If P is being multiplied by 2/9 and is not part of the denominator:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "1. Subtract 1 from both sides of the equation:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "N - 1 = (2/9)P + 1 - 1 -----> N - 1 = (2/9)P\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "2. Multiply both sides of the equation by 9 -----> 9(N - 1) = 2P\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "3. Divide both sides of the equation by 2 -----> \"%289%28N+-+1%29%29%2F2+=+P\"
\n" ); document.write( "
\n" );