document.write( "Question 9336: what are the intercepts in this problem
\n" ); document.write( "x^2 + x -2
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Algebra.Com's Answer #5048 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
First, before you can have intercepts, you have to have the equation for a graph. Do you mean find the intercepts for \"+y+=+x%5E2+%2Bx+-+2\"\r
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\n" ); document.write( "\n" ); document.write( "If so, then the y intercept is always where x=0. If x = 0, then y = -2. That's the y-intercept.\r
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\n" ); document.write( "\n" ); document.write( "The x-intercept is always where y = 0. If y=0, this means that
\n" ); document.write( "\"0+=+x%5E2+%2B+x+-2\" which is a quadratic equation. (See my Lesson Plan on Solving Quadratic Equations and also Factoring Trinomials.) This quadratic equation can be solved by factoring.\r
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\n" ); document.write( "\n" ); document.write( "\"+0+=+x%5E2+%2B+x+-2\"
\n" ); document.write( "\"+0+=+%28x%2B2%29%28x-1%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Set each factor equal to zero:
\n" ); document.write( "x+2 = 0
\n" ); document.write( "x= -2\r
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\n" ); document.write( "\n" ); document.write( "x-1 = 0
\n" ); document.write( "x=1\r
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\n" ); document.write( "\n" ); document.write( "Therefore, x = -2 and x= 1 are the x-intercepts.\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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