document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=837955>Question 837955</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a circle is given by the formula A=piR^2 where r is the radius. If increasing the radius of a circle by 1 inch gives the resulting circle an area of 100 times pi square inches, what is the radius of the original circle <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #504798 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=504798\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area of a circle is given by the formula A=piR^2 where r is the radius. If increasing the radius of a circle by 1 inch gives the resulting circle an area of 100 times pi square inches, what is the radius of the original circle <BR>\n" );
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document.write( "Increased Area = pi(R+1)^2 = pi(R^2+2R+1) = piR^2 + pi(2R+1)<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "2R+1 = 100<BR>\n" );
document.write( "2R = 99<BR>\n" );
document.write( "R = 49.5 (original radius)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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