document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=837551>Question 837551</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Leaving the logs in the answer, solve for x. 5^(3x+1)+2=9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #504790 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=504790\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Leaving the logs in the answer, solve for x. 5^(3x+1)+2=9<BR>\n" );
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document.write( "5^(3x+1)+2=9<BR>\n" );
document.write( "5^(3x+1)=7<BR>\n" );
document.write( "(3x+1)log(5)=log(7)<BR>\n" );
document.write( "3x+1=log(7)/log(5)<BR>\n" );
document.write( "3x=(log(7)/log(5))-1<BR>\n" );
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