document.write( "Question 837626: I have a problem: For a world Peace day celebration the students at cabot high school are making a 6 m by 8 m flag. Each of the six grades will create a motif to honor the people of the six inhabited continets. Sketch three possible ways to divide the flag. One into six congruent triangles; one into sixs triangles with equal area but none congruent; and one into six congruent trapezoids. Give measuresments or makings on your sketches so each class knows it has equal area \n" ); document.write( "
Algebra.Com's Answer #504730 by KMST(5328)\"\" \"About 
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These are the first ideas that came to my mind.
\n" ); document.write( "The possibilities are probably endless, but it is hard enough to draw these three.
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\n" ); document.write( "Six congruent triangles:
\n" ); document.write( " Six right triangles with legs measuring 2m and 8m.
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\n" ); document.write( "Six congruent trapezoids:
\n" ); document.write( " Six trapezoids with bases measuring 5m and 3m, and a 2m side perpendicular to the bases, for a 2m height.
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\n" ); document.write( "Six triangles with equal area but none congruent:
\n" ); document.write( "(I would draw this on grid paper. I will draw a grid of 1m by 1m squares).
\n" ); document.write( " The red lines divide the whole 8m by 6m rectangle (area=(8m)(6m)=48 square meters) into 6 triangles, each with an area of 8 square meters.
\n" ); document.write( "Triangle A is an isosceles triangle with an 8m base and a 2m height, not congruent to any of the other triangles.
\n" ); document.write( "You could say that non-congruent triangles B and C have the same base and height (a 2m base and an 8m height). They are obviously not congruent to any of the other triangles.
\n" ); document.write( "Triangle D is an isosceles triangle with base and height measuring 4 m.
\n" ); document.write( "Triangle E also has a base and a height measuring 4m,but it is not isosceles, and not congruent to any other triangle.
\n" ); document.write( "All those triangles have areas that can be calculated as \"base%2Aheight%2F2\" , and each has an area of 8 square meters:
\n" ); document.write( "\"8%2A2%2F2=8\"
\n" ); document.write( "\"2%2A8%2F2=8\"
\n" ); document.write( "\"4%2A4%2F2=8\"
\n" ); document.write( "Their areas add up to \"5%2A8\"square meters =\"40\"square meters.
\n" ); document.write( "The remaining triangle (triangle F) must have an area of
\n" ); document.write( "48 square meters - 40 square meters = 8 square meters.
\n" ); document.write( "If the class assigned triangle F is not convinced enough, you could tell them that E and F together form a triangle with a 4m base and an 8m height, and that E+F triangle is divided into two equal parts by a median, the line segment between triangles E and F.
\n" ); document.write( "If they are still not convinced, they can use Heron's formula to calculate the area, using the lengths of the sides:
\n" ); document.write( "5m (for the side that is half a diagonal of the rectangle), \"sqrt%2817%29\" meters, and \"sqrt%2817%29\" meters.
\n" ); document.write( "In that case, I would use the version that calculates the area as
\n" ); document.write( "\"%281%2F4%29%2Asqrt%284a%5E2b%5E2-%28a%5E2%2Bb%5E2-c%5E2%29%5E2%29\" .
\n" ); document.write( "(The letters \"a\" , \"b\" and \"c\" are the side lengths).
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