document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=837607>Question 837607</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Kendra has $13.20 in dimes and quarters. If she has 4 times as many quarters as dimes, how many of each coin does she have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #504677 by </B><A HREF=/tutors/aboutme.mpl?userid=josh_jordan><B>josh_jordan(263)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josh_jordan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=josh_jordan><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=504677\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To solve, we need to set this word problem up as a set of equations.  We are told that Kendra has $13.20 in dimes and quarters.  We know that a dime is = .10 and a quarter is equal to .25.  So, our first equation would look like:\r<BR>\n" );
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document.write( ".10d + .25q = 13.20, where d=dimes and q=quarters\r<BR>\n" );
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document.write( "Next, we are told that the number of quarters is 4 times the number of dimes.  In other words\r<BR>\n" );
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document.write( "q = 4d\r<BR>\n" );
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document.write( "Now, we can substitute 4d for q in equation 1:\r<BR>\n" );
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document.write( ".10d + .25(4d) = 13.20 ----->\r<BR>\n" );
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document.write( ".10d + 1d = 13.20 ----->\r<BR>\n" );
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document.write( "1.10d = 13.20\r<BR>\n" );
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document.write( "Now, we can divide both sides of this equation by 1.10:\r<BR>\n" );
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document.write( "d = 13.20/1.10 ----->\r<BR>\n" );
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document.write( "d = 12\r<BR>\n" );
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document.write( "Therefore, Kendra has 12 dimes.  We know that the number of quarters is 4 times the number of dimes.  So, 4 * 12 = 48.  Hence, we have 48 quarters.  \r<BR>\n" );
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document.write( "ANSWER:  12 dimes & 48 quarters </SPAN>\n" );
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