document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=837620>Question 837620</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm thoroughly stuck on this trig problem: [(cosine of theta times cotangent of theta) over (1 minus sin of theta)] minus 1 equals cosecant of theta. I've tried converting everything to sines and cosines, and that didn't work, and I tried everything I could think of with the fundamental identities and nothing worked there either. Any help would be greatly appreciated. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #504659 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=504659\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> cos*cot/(1 - sin) - 1 = csc<BR>\n" );
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document.write( "You didn't say what you want to do.<BR>\n" );
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document.write( "(cos^2/sin)/(1 - sin) - 1 = csc<BR>\n" );
document.write( "((1-sin^2)/sin)/(1-sin) - 1 = csc<BR>\n" );
document.write( "(1 + sin)/sin  - 1 = csc<BR>\n" );
document.write( "1/sin + sin/sin - 1 = csc<BR>\n" );
document.write( "1/sin = csc<BR>\n" );
document.write( "csc = csc<BR>\n" );
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