document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=837613>Question 837613</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can't figure this out for the life of me.Thanks in advance\r<BR>\n" );
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document.write( "(3m^2/3-4m^-1/3) factor out m^-1/3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #504657 by </B><A HREF=/tutors/aboutme.mpl?userid=josh_jordan><B>josh_jordan(263)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josh_jordan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=josh_jordan><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=504657\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello.  This is how it would look if m^(-1/3) was factored out of 3m^(2/3)-4m^(-1/3):\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m%5E%28-1%2F3%29%283m+-+4%29 ALIGN=MIDDLE  ALT=\"m%5E%28-1%2F3%29%283m+-+4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "This is why:\r<BR>\n" );
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document.write( "When you multiply m^(-1/3) by 3m, you are ADDING the exponents.  So, you would add -1/3 and 1, which would be 1 - 1/3 = 2/3, hence 3m^(2/3)\r<BR>\n" );
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document.write( "When you multiply m^(-1/3) by 4, you get 4m^(-1/3), which gives you your original equation.  So, again, the answer is\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m%5E%28-1%2F3%29%283m-4%29 ALIGN=MIDDLE  ALT=\"m%5E%28-1%2F3%29%283m-4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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