document.write( "Question 837616: A boat traveled 210 miles in 10 hours against the current. The boat then returned with the current in 6 hours. What were the speeds of the boat and of the current? \n" ); document.write( "

Algebra.Com's Answer #504656 by mananth(16946) $\"\"$ $\"About$

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boat speed =x mph
\n" ); document.write( "current speed =y mph
\n" ); document.write( "against current 10 hours
\n" ); document.write( "with current 6 hours
\n" ); document.write( "
\n" ); document.write( "Distance against 210 miles distance with 210 miles
\n" ); document.write( "t=d/r against current -
\n" ); document.write( "210.00 / ( x - y )= 10.00
\n" ); document.write( "10.00 ( x - y ) = 6.00
\n" ); document.write( "10.00 x - 10.00 y = 210.00 ....................1
\n" ); document.write( "
\n" ); document.write( "210.00 / ( x + y )= 6.00
\n" ); document.write( "6.00 ( x + y ) = 210.00
\n" ); document.write( "6.00 x + 6.00 y = 210.00 ...............2
\n" ); document.write( "Multiply (1) by 3.00
\n" ); document.write( "Multiply (2) by 5.00
\n" ); document.write( "we get
\n" ); document.write( "30.00 x + -30.00 y = 630.00
\n" ); document.write( "30.00 x + 30.00 y = 1050.00
\n" ); document.write( "60.00 x = 1680.00
\n" ); document.write( "/ 60.00
\n" ); document.write( "x = 28.00 mph
\n" ); document.write( "
\n" ); document.write( "plug value of x in (1) y
\n" ); document.write( "10.00 x -10.00 y = 210.00
\n" ); document.write( "280.00 -10.00 -280.00 = 210.00
\n" ); document.write( "-10.00 y = 210.00
\n" ); document.write( "-10.00 y = -70.00 mph
\n" ); document.write( " y = 7.00
\n" ); document.write( "boat speed 28.00 mph
\n" ); document.write( "current speed 7.00 mph
\n" ); document.write( "
\n" ); document.write( "m.ananth@hotmail.ca
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