document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=837580>Question 837580</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if 0 degrees < X degrees < 90 degrees and Sin X= 1/2, then Cos X=?\r<BR>\n" );
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document.write( " i have the answer and the steps to this problem but i need it broken down and why, cause i absolutely don't understand how to get the answer i want to be able to  understand how to do a problem like this.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #504643 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=504643\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if 0 degrees < X degrees < 90 degrees and Sin X= 1/2, then Cos X=?\r<BR>\n" );
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document.write( "By definition: sin = y/r<BR>\n" );
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document.write( "Since sin(x) = 1/2, y = 1 and r = 2<BR>\n" );
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document.write( "Therefore y = sqrt[2^2-1^2] = sqrt(3)<BR>\n" );
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document.write( "Your Problem:<BR>\n" );
document.write( "By definitiion: cos = x/r<BR>\n" );
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document.write( "So cos(X) = x/r = sqrt(3)/2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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