document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=837455>Question 837455</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a coffee shop decides to blend a coffee that sells for 12$ per pound with a coffee that sells for $9 per pound to produce a blend that will sell for $10 a pound. How much of each should be used to yield 20 pound o the new blend? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #504594 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=504594\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a coffee shop decides to blend a coffee that sells for 12$ per pound with a coffee that sells for $9 per pound to produce a blend that will sell for $10 a pound. How much of each should be used to yield 20 pound o the new blend?<BR>\n" );
document.write( "***<BR>\n" );
document.write( "let x=amount of $12/pound coffee<BR>\n" );
document.write( "20-x=amount of $9/pound coffee<BR>\n" );
document.write( "12x+9(20-x)=10*20<BR>\n" );
document.write( "12x+180-9x=200<BR>\n" );
document.write( "3x=20<BR>\n" );
document.write( "x=20/3<BR>\n" );
document.write( "amount of $12/pound coffee should be used=20/3 lbs<BR>\n" );
document.write( "amount of $9/pound coffee should be used=40/3 lbs\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );