document.write( "Question 837383: How are you suppose to cancel out ?\r
\n" ); document.write( "\n" ); document.write( "(4x+2y=66)
\n" ); document.write( "(12x+8y=220)
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Algebra.Com's Answer #504591 by mxgirl22(39)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "1.) (4x+2y=66)
\n" ); document.write( "2.) (12x+8y=220)\r
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\n" ); document.write( "\n" ); document.write( "I'm assuming you mean solve for x and y.\r
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\n" ); document.write( "\n" ); document.write( "1st) I can see x's will be easy to cancel out. So use -3 to make 4x into -12x. You need to multiply everything in equation 1.) by -3.\r
\n" ); document.write( "\n" ); document.write( "1.) -3(4x+2y=66)
\n" ); document.write( "2.) (12x+8y=220)
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\n" ); document.write( " -12x-6y=-198 <---This will be your new #1\r
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\n" ); document.write( "\n" ); document.write( "2nd) Combine.\r
\n" ); document.write( "\n" ); document.write( "1.) -12x-6y=-198
\n" ); document.write( "2.) 12x+8y=220
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\n" ); document.write( " 2y=22
\n" ); document.write( " 2y/2=22/2
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\n" ); document.write( " y=11 <----- Solution for y
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\n" ); document.write( "3rd) Solve for x. Plug in y=11. Use one of the original equations.\r
\n" ); document.write( "\n" ); document.write( "1.) 4x+2y=66
\n" ); document.write( " 4x+2(11)=66
\n" ); document.write( " 4x+22=66
\n" ); document.write( " 4x+22-22=66-22
\n" ); document.write( " 4x=44
\n" ); document.write( " 4x/4=44/4\r
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\n" ); document.write( "\n" ); document.write( " x=11 <----- Solution for x
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\n" ); document.write( "4th) Just for safety...I'm going to plug in the values I found (x=11 and y=11) into equation 2.\r
\n" ); document.write( "\n" ); document.write( "2.) 12x+8y=220
\n" ); document.write( " 12(11)+8(11)=220
\n" ); document.write( " 132+88=220
\n" ); document.write( " 220=220\r
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\n" ); document.write( "\n" ); document.write( "And it checks!\r
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\n" ); document.write( "\n" ); document.write( "So answer is: x=11 and y=11\r
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