document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=837257>Question 837257</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A student averaged 86% on his first two exams. What must he earn on his 3rd exam to have an A average? (assume an A=90%-100%). Write an inequality representing this situation and solve it. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #504540 by </B><A HREF=/tutors/aboutme.mpl?userid=sheldonbbtrocks><B>sheldonbbtrocks(115)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sheldonbbtrocks><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sheldonbbtrocks><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=504540\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well we could assume that this student got an 86% on all the exams, even though he probably not have, we need to add 3 numbers that average 86, and this is the easiest solution. Also, because he needs a 90% or better average on 4 exams, we must account for this by multiplying 90 by 4. This yields:\r<BR>\n" );
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document.write( "86+86+86+x<=360\r<BR>\n" );
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document.write( "Now solve:\r<BR>\n" );
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document.write( "258+x<=360\r<BR>\n" );
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document.write( "x<=102\r<BR>\n" );
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document.write( "So John must somehow earn [102%] on his next exam to get an A average. </SPAN>\n" );
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