document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=837220>Question 837220</A>: <I><SPAN STYLE=\"word-break: break-all;\"> help me set up equation and solve.<BR>\n" );
document.write( "A farmer grows only sunflowers and flax on his 240-acre farm. This year, he planted 80 more acres of sunflower than of flax. How many acres of each crop has he planted? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #504521 by </B><A HREF=/tutors/aboutme.mpl?userid=LinnW><B>LinnW(1048)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LinnW><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=LinnW><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=504521\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> set f = acres of flax  , s = acres of sunflowers<BR>\n" );
document.write( "f + s = 240<BR>\n" );
document.write( "s = f + 80<BR>\n" );
document.write( "substitute (f + 80) for s in f + s = 240<BR>\n" );
document.write( "f + (f + 80) = 240<BR>\n" );
document.write( "2f + 80 = 240<BR>\n" );
document.write( "add -80 to each side<BR>\n" );
document.write( "2f = 160<BR>\n" );
document.write( "divide each side by 2<BR>\n" );
document.write( "f = 80<BR>\n" );
document.write( "since s = f + 80 ,<BR>\n" );
document.write( "s = 80 + 80<BR>\n" );
document.write( "s = 160 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );