document.write( "Question 9339: Here is a word problem....I always have problems with word problems. \r
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\n" ); document.write( "\n" ); document.write( "The width of a rectangle is 8 feet less than the length. If the area is 20 square feet, find the length and width. \r
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\n" ); document.write( "\n" ); document.write( "Can you please show me how you get the answer as well? I believe the answer is 10 feet = length and width is 2 feet.\r
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Algebra.Com's Answer #5045 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
Let x = the phrase at the end of the first sentence, which is to say,
\n" ); document.write( "let x = length.\r
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\n" ); document.write( "\n" ); document.write( "Then x-8 = width\r
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\n" ); document.write( "\n" ); document.write( " LW = Area
\n" ); document.write( " x(x-8) = 20
\n" ); document.write( "\"x%5E2+-+8x+-20+=+0\"
\n" ); document.write( "\"+%28x+-+10%29%28x%2B2%29+=+0+\"
\n" ); document.write( "x= 10 and x= -2 \r
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\n" ); document.write( "\n" ); document.write( "You must reject the negative value, so the
\n" ); document.write( "length x= 10 feet,
\n" ); document.write( "width x-8 = 2 feet. \r
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\n" ); document.write( "\n" ); document.write( "The check of course is that LW= 10*2 = 20 ft^2.\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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