document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=70656>Question 70656</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log_3(x) - log_9(x) = 2\r<BR>\n" );
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document.write( "First i changed the base, by doing a little basic<BR>\n" );
document.write( "reasoning.  Suppose\r<BR>\n" );
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document.write( "  y = log_9(x)\r<BR>\n" );
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document.write( "Then\r<BR>\n" );
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document.write( "      9^y = x\r<BR>\n" );
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document.write( "  (3^2)^y = x\r<BR>\n" );
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document.write( "   3^(2y) = x\r<BR>\n" );
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document.write( "       2y = log_3(x)\r<BR>\n" );
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document.write( "       y = log_3(x)/ 2\r<BR>\n" );
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document.write( "Now you have\r<BR>\n" );
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document.write( "             <BR>\n" );
document.write( "  log_3(x) - (1/2)log_3 = 2<BR>\n" );
document.write( "                <BR>\n" );
document.write( "but im stuck from here, please help me with solving trhe x? ironicly i know the answer is 81, but i came to that but doing trial and error log_3(79) - log_9(79) = 1.9877etc than log_3(81) - log_9(81) = 2. I am sure there is a much simplar way of dealing with this but i dont know how to deal with the x above. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50449 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50449\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve for x:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Log%5B3%5Dx+-Log%5B9%5Dx+=+2 ALIGN=MIDDLE  ALT=\"Log%5B3%5Dx+-Log%5B9%5Dx+=+2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Change the base of the first log from 3 to 9<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Log%5B3%5Dx+=+%28Log%5B9%5Dx%29%2FLog%5B9%5D3 ALIGN=MIDDLE  ALT=\"Log%5B3%5Dx+=+%28Log%5B9%5Dx%29%2FLog%5B9%5D3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "But <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Log%5B9%5D3+=+1%2F2 ALIGN=MIDDLE  ALT=\"Log%5B9%5D3+=+1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > So now you have:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Log%5B3%5Dx+=+2Log%5B9%5Dx ALIGN=MIDDLE  ALT=\"Log%5B3%5Dx+=+2Log%5B9%5Dx\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2Log%5B9%5Dx-Log%5B9%5Dx+=+2 ALIGN=MIDDLE  ALT=\"2Log%5B9%5Dx-Log%5B9%5Dx+=+2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract the logarithms.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Log%5B9%5Dx+=+2 ALIGN=MIDDLE  ALT=\"Log%5B9%5Dx+=+2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Rewrite in exponential form..<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=9%5E2+=+x ALIGN=MIDDLE  ALT=\"9%5E2+=+x\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+81 ALIGN=MIDDLE  ALT=\"x+=+81\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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