document.write( "Question 837104: landon can climb a certain hill at a rate that is 1.5 mph slower than his rate coming down the hill. If it takes him 4 hours to climb the hill and 168 minutes to come down the hill, what is his rate coming down? \n" ); document.write( "
Algebra.Com's Answer #504481 by josgarithmetic(39625)\"\" \"About 
You can put this solution on YOUR website!
r = rate going down the hill\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "______________speed___________time______________distance
\n" ); document.write( "UPHILL________r-1.5___________4________________\"%28r-1.5%29%2A4\"
\n" ); document.write( "DOWNHILL_______r_____________168/60=2.8_________\"r%2A%282.8%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The division by 60 for downhill is because 60 minutes make 1 hour.
\n" ); document.write( "Both directions are the same distance quantity.
\n" ); document.write( "\"highlight_green%28%28r-1.5%29%2A4=r%282.8%29%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"4r-6=2.8r\"
\n" ); document.write( "\"4r-2.8r=6\"
\n" ); document.write( "\"1.2r=6\"
\n" ); document.write( "\"r=6%2F1.2\"
\n" ); document.write( "\"highlight%28r=5%29\"
\n" ); document.write( "
\n" );