document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=836995>Question 836995</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 7 more than twice the other number. If the sum of the two numbers is 16, find the two numbers.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #504433 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=504433\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One number is 7 more than twice the other number. If the sum of the two numbers is 16, find the two numbers. <BR>\n" );
document.write( "----------------------------<BR>\n" );
document.write( "Equations:<BR>\n" );
document.write( "2x = y+7<BR>\n" );
document.write( "x + y = 16<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "Substitute for \"y\" and solve for \"x\"::<BR>\n" );
document.write( "y = 2x-7<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "x + 2x-7 = 16<BR>\n" );
document.write( "3x = 23<BR>\n" );
document.write( "x = 7 2/3<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "Solve for \"y\":<BR>\n" );
document.write( "y = 2(23/3)-7 = 46/3 - 7 = (46-21)/3 = 25/3<BR>\n" );
document.write( "-------------------------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============== </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );