document.write( "Question 836973: There are 21 wheels at the bike shop. The wheels will be used to build tricycles and bicycles. There will be half as many tricycles as bicycles. How much of each type of bike will be built? \n" ); document.write( "
| Algebra.Com's Answer #504430 by dfrazzetto(283)     You can put this solution on YOUR website! \n" ); document.write( "Set:\r \n" ); document.write( "\n" ); document.write( "# of Bicycles = B\r \n" ); document.write( "\n" ); document.write( "# of wheels needed per bike = 2B\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "# of Tricycles = T\r \n" ); document.write( "\n" ); document.write( "# of wheels needed per trike = 3T\r \n" ); document.write( "\n" ); document.write( "T = 1/2B \n" ); document.write( "B = 2T\r \n" ); document.write( "\n" ); document.write( "2B + 3T = 21 total wheels\r \n" ); document.write( "\n" ); document.write( "Plugging in B = 2T:\r \n" ); document.write( "\n" ); document.write( "2(2T) + 3T = 21\r \n" ); document.write( "\n" ); document.write( "4T + 3T = 21\r \n" ); document.write( "\n" ); document.write( "7T = 21\r \n" ); document.write( "\n" ); document.write( "T = 3 \n" ); document.write( "B = 6\r \n" ); document.write( "\n" ); document.write( "6 Bicycles and 3 Tricycles\r \n" ); document.write( "\n" ); document.write( "CHECK:\r \n" ); document.write( "\n" ); document.write( "6(2 wheels per bike) + 3(3 wheels per trike) = 12 + 9 = 21 Wheels total\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |