document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=70661>Question 70661</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Evaluate the logarithm loga63 by using properties of logarithms and the following: loga3=5 loga7=2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50442 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50442\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Evaluate the logarithm loga63 by using properties of logarithms and the following: loga3=5 loga7=2<BR>\n" );
document.write( "SINCE ALL LOGS ARE TO BASE A LET ME DROP IT AND TAKE IT AS UNDERSTOOD,<BR>\n" );
document.write( "FOR CONVENIENCE IN TYPING..<BR>\n" );
document.write( "LOG(63)=LOG(7*3*3)=LOG(7)+LOG(3)+LOG(3)<BR>\n" );
document.write( "=2+5+5=12 </SPAN>\n" );
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