document.write( "Question 836881: On a 6 day trip, michael schmitz rented a car for $53 per day at weekday rates and $35 per day at weekend rates. If his total bill was $265, how many days did he rent at each rate? \n" ); document.write( "
Algebra.Com's Answer #504408 by josgarithmetic(39620)\"\" \"About 
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The six-day trip should indicate that he rented for 5 weekdays and 1 weekend-day. Does that work when given the second part of having spent $265?\r
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\n" ); document.write( "\n" ); document.write( "5*53+1*35=300; NO.
\n" ); document.write( "This does not match $265.\r
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\n" ); document.write( "\n" ); document.write( "Try variables.
\n" ); document.write( "x = how many weekdays
\n" ); document.write( "y = how many weekend days\r
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\n" ); document.write( "\n" ); document.write( "\"x%2By=6\"
\n" ); document.write( "and
\n" ); document.write( "\"53x%2B35y=265\"
\n" ); document.write( "-
\n" ); document.write( "-
\n" ); document.write( "\"y=6-x\";
\n" ); document.write( "\"53x%2B35%286-x%29=265\"
\n" ); document.write( "\"53x%2B210-35x=265\"
\n" ); document.write( "\"53x-35x=55\"
\n" ); document.write( "\"18x=55\"
\n" ); document.write( "\"x=55%2F18=3.06\", appears to make poor or no sense.\r
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\n" ); document.write( "\n" ); document.write( "Possible, he spent all six days as weekdays with no weekends, but this also makes poor sense.
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