document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=836815>Question 836815</A>: <I><SPAN STYLE=\"word-break: break-all;\"> work out the value of the series<BR>\n" );
document.write( "1+2+4+5+7+8+10+11+......+50   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #504401 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=504401\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1+2+3+...+50 = 50*51/2 = 1275\r<BR>\n" );
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document.write( "We are subtracting off the multiples of 3 from 3 to 48, inclusive, in which 3+6+9+...+48 = 3(1+2+...+16) = 3(16*17/2) = 408. The sum is equal to 1275 - 408 = 867. </SPAN>\n" );
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