document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=836687>Question 836687</A>: <I><SPAN STYLE=\"word-break: break-all;\"> So, my question on homework is how to do this substitution equation. \r<BR>\n" );
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document.write( "The homework question is: <BR>\n" );
document.write( "5.) Solve by substitution : y = -3x  and 2x - 3y = 22 \r<BR>\n" );
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document.write( "Please help, and thank you in advance. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #504325 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=504325\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y = -3x and 2x - 3y = 22<BR>\n" );
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document.write( "Using:<BR>\n" );
document.write( "y = -3x<BR>\n" );
document.write( "We \"substitute\" the value of 'y' with '-3x' (since they are equal) into:<BR>\n" );
document.write( "2x - 3y = 22<BR>\n" );
document.write( "2x - 3(-3x) = 22<BR>\n" );
document.write( "2x + 9x = 22<BR>\n" );
document.write( "11x = 22<BR>\n" );
document.write( "x = 2  (answer for x)<BR>\n" );
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document.write( "Answer for y, we substitute the above into:<BR>\n" );
document.write( "y = -3x<BR>\n" );
document.write( "y = -3(2)<BR>\n" );
document.write( "y = -6 (answer for y)<BR>\n" );
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document.write( "Solution: (x,y) = (2, -6)<BR>\n" );
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