document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=70587>Question 70587</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0072934735/algebrahomeworkh>Intermediate Algerba  </A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> (3,_),(_,-1),2x-3y=5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50423 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50423\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (3,_),(_,-1),2x-3y=5<BR>\n" );
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document.write( "This is two separate problems.  The first problem is that you are given (3,_) and the equation<BR>\n" );
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document.write( "2x - 3y = 5<BR>\n" );
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document.write( "The 3 in (3,___) represents x.  Substitute 3 for x in the equation and solve for y:<BR>\n" );
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document.write( "2(3) - 3y = 5<BR>\n" );
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document.write( "Multiply out the left side to get:<BR>\n" );
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document.write( "6 - 3y = 5<BR>\n" );
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document.write( "Subtract 6 from both sides:<BR>\n" );
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document.write( "-3y = -1<BR>\n" );
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document.write( "Divide both sides by -3 to end up with:<BR>\n" );
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document.write( "y = (-1/-3) = 1/3<BR>\n" );
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document.write( "So the missing entry in (3,_) is 1/3 and the answer becomes (3, 1/3)<BR>\n" );
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document.write( "The second problem involves the answer set (_, -1) for the equation 2x - 3y = 5. Substitute<BR>\n" );
document.write( "-1 for y in the equation to get:<BR>\n" );
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document.write( "2x - 3(-1) = 5<BR>\n" );
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document.write( "And multiply out to get:<BR>\n" );
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document.write( "2x + 3 = 5<BR>\n" );
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document.write( "Subtract 3 from both sides:<BR>\n" );
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document.write( "2x = 2<BR>\n" );
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document.write( "Divide both sides by 2 and the result is:<BR>\n" );
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document.write( "x = 1<BR>\n" );
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document.write( "So the missing x value in (_, -1) is 1 and the answer set is (1, -1)<BR>\n" );
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document.write( "Hope this helps you to understand what the problem was looking for.  \r<BR>\n" );
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