document.write( "Question 836481: The ten's digit of a three-digit number is twice the unit's digit.The hundred's digit of the number is twice the ten's digit. The number formed by reversing the digits of the number is 594 less than it.Find the number. \n" ); document.write( "
Algebra.Com's Answer #504219 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! \n" ); document.write( "let a = the 100's digit \n" ); document.write( "let b = the 10's \n" ); document.write( "let c = the units \n" ); document.write( "then \n" ); document.write( "100a + 10b + c = \"the number\" \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement: \n" ); document.write( "The ten's digit of a three-digit number is twice the unit's digit. \n" ); document.write( "b = 2c \n" ); document.write( "or \n" ); document.write( "c = .5b \n" ); document.write( "The hundred's digit of the number is twice the ten's digit. \n" ); document.write( "a = 2b \n" ); document.write( " The number formed by reversing the digits of the number is 594 less than it \n" ); document.write( "100a + 10b + c = 100c + 10b + a + 594 \n" ); document.write( "100a - a + 10b - 10b = 100c - c + 594 \n" ); document.write( "99a = 99c + 594 \n" ); document.write( "simplify, divide by 99 \n" ); document.write( "a = c + 6 \n" ); document.write( "replace a with 2b, replace c with .5b \n" ); document.write( "2b = .5b + 6 \n" ); document.write( "2b - .5b = 6 \n" ); document.write( "1.5b = 6 \n" ); document.write( "b = 6/1.5 \n" ); document.write( "b = 4 \n" ); document.write( "then \n" ); document.write( "a = 2(4) \n" ); document.write( "a = 8 \n" ); document.write( "and \n" ); document.write( "c = .5(4) \n" ); document.write( "c = 2 \n" ); document.write( ": \n" ); document.write( "the number is 842 \n" ); document.write( ": \n" ); document.write( " you can check this in the statement: \n" ); document.write( "\"The number formed by reversing the digits of the number is 594 less than it\" \n" ); document.write( " |