document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=70574>Question 70574</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0072549017/algebrahomeworkh>Beginning Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Factor each of the following trinomials completely: 2a^3 - 52a^2 b + 96ab^2\r<BR>\n" );
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document.write( "The answer I got for the equation was:<BR>\n" );
document.write( "(2a)(a^2 - 26ab + 48b^2)\r<BR>\n" );
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document.write( "Is this correct? If not could you show me how to get the correct answer. Thanks.<BR>\n" );
document.write( "Sorry I could not post all of my work.. too long. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50421 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50421\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Factor each of the following trinomials completely: 2a^3 - 52a^2 b + 96ab^2<BR>\n" );
document.write( "The answer I got for the equation was:<BR>\n" );
document.write( "(2a)(a^2 - 26ab + 48b^2).....OK SO FAR BUT YOU CAN CONTINUE<BR>\n" );
document.write( "=2A[A^2-24AB-2AB+48B^2]...FIND 2 FACTORS OF 48 WHOSE SUM IS 26...48=(-24)*(-2)<BR>\n" );
document.write( "=2A[A(A-24B)-2B(A-24B)]<BR>\n" );
document.write( "=2A(A-24B)(A-2B)  IS THE ANSWER. \r<BR>\n" );
document.write( "\n" );
document.write( "Is this correct? If not could you show me how to get the correct answer. Thanks.<BR>\n" );
document.write( "Sorry I could not post all of my work.. too long. </SPAN>\n" );
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