document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=836365>Question 836365</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a 40 -litre mixture of milk and water,the water is 10%.How much water is to be added to get a new mixture in which the water is 20%. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #504135 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=504135\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> w is how much water to add to increase the \"concentration of water\" \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2840%2A10%2B100%2Aw%29%2F%2840%2Bw%29=20 ALIGN=MIDDLE  ALT=\"%2840%2A10%2B100%2Aw%29%2F%2840%2Bw%29=20\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Solve for w.\r<BR>\n" );
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document.write( "Water in mixtures or solutions is usually treated as the carrier, and not as one of the materials to be referenced for concentration.  This exercise reverses that idea.  \r<BR>\n" );
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document.write( "My profile page has a lesson for this. </SPAN>\n" );
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