document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=836354>Question 836354</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the area of a circle inscribed in a right triangle with sides of length 8 metre, 15 metre and 17 metre is </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #504116 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=504116\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area = (1/2)(8 m)(15 m) = 60 m^2\r<BR>\n" );
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document.write( "Also, Area = (inradius)*(semi-perimeter), so\r<BR>\n" );
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document.write( "60 m^2 = (inradius)*(20 m) --> inradius = 3 m. The area of the inscribed circle is 9pi m^2. </SPAN>\n" );
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