document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=836332>Question 836332</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter, P, of a rectangular concrete slab is 46 m and it's area, A, is 90 m^2.  Use the formula P + 2l + 2w. Determine the dimensions of the slab. Show your work.<BR>\n" );
document.write( "I have tried to do this and keep getting the most ridiculous answers.  This question has really stumped me and I have come to a stand still. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #504105 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=504105\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A = LW ... area of rectangle\r<BR>\n" );
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document.write( "90 = LW\r<BR>\n" );
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document.write( "LW = 90\r<BR>\n" );
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document.write( "L = 90/W\r<BR>\n" );
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document.write( "P = 2L + 2W\r<BR>\n" );
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document.write( "46 = 2L + 2W\r<BR>\n" );
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document.write( "46 = 2(90/W) + 2W\r<BR>\n" );
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document.write( "46 = 180/W + 2W\r<BR>\n" );
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document.write( "W*(46) = W(180/W + 2W) ... Multiply both sides by W so we can clear out that fraction.\r<BR>\n" );
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document.write( "W*(46) = W(180/W) + W(2W)\r<BR>\n" );
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document.write( "46W = 180 + 2W^2\r<BR>\n" );
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document.write( "0 = 180 + 2W^2 - 46W\r<BR>\n" );
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document.write( "2W^2 - 46W + 180 = 0\r<BR>\n" );
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document.write( "2(W^2 - 23W + 90) = 0\r<BR>\n" );
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document.write( "W^2 - 23W + 90 = 0/2\r<BR>\n" );
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document.write( "W^2 - 23W + 90 = 0\r<BR>\n" );
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document.write( "(W - 18)(W - 5) = 0\r<BR>\n" );
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document.write( "W - 18 = 0 or W - 5 = 0\r<BR>\n" );
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document.write( "W = 18 or W = 5\r<BR>\n" );
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document.write( "if the width is W = 18, then the length is L = 90/W = 90/18 = 5.\r<BR>\n" );
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document.write( "if the width is W = 5, then the length is L = 90/W = 90/5 = 18.\r<BR>\n" );
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document.write( "So regardless of which value you pick for W, the other value for L will be the other solution.\r<BR>\n" );
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document.write( "In essence, the dimensions are <font color=\"red\">18 meters by 5 meters</font>\r<BR>\n" );
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document.write( "Check: \r<BR>\n" );
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document.write( "A = LW = 18*5 = 90 square meters ... area checks out\r<BR>\n" );
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document.write( "P = 2L + 2W = 2*18 + 2*5 = 36+10 = 46 meters ... perimeter checks out </SPAN>\n" );
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