document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=836304>Question 836304</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have sent in my graph and solutions to my school and they sent my work back saying my vertex was wrong.  The equation is -3x^2-6x-5. I had (0,-5) as my vertex and I can't figure out why its wrong or what else it could. Please help. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #504082 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=504082\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In general, if you have y = ax^2 + bx + c, the axis of symmetry is x = -b/(2a)\r<BR>\n" );
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document.write( "In this case, a = -3, b = -6\r<BR>\n" );
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document.write( "x = -b/(2a)\r<BR>\n" );
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document.write( "x = -(-6)/(2(-3))\r<BR>\n" );
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document.write( "x = 6/(-6)\r<BR>\n" );
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document.write( "x = -1\r<BR>\n" );
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document.write( "The axis of symmetry, and the x coordinate of the vertex, is x = -1\r<BR>\n" );
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document.write( "Plug this into the given equation to find the y coordinate of the vertex\r<BR>\n" );
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document.write( "y = -3x^2-6x-5\r<BR>\n" );
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document.write( "y = -3(-1)^2-6(-1)-5\r<BR>\n" );
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document.write( "y = -3(1)-6(-1)-5\r<BR>\n" );
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document.write( "y = -3 + 6 - 5\r<BR>\n" );
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document.write( "y = -2\r<BR>\n" );
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document.write( "So the vertex is <font color=\"red\">(-1,-2)</font> </SPAN>\n" );
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