document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=836295>Question 836295</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Cement, gravel, and sand are to be combined into a mixture in the ratio of 3:5:7 respectively. If 5 tons of cement are available, how many tons of the mixture can be made? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #504075 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=504075\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Cement, gravel, and sand are to be combined into a mixture in the ratio of 3:5:7 respectively. If 5 tons of cement are available, how many tons of the mixture can be made?<BR>\n" );
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document.write( "3:5:7 is the same as 3x:5x:7x where 3x is the amount of cement:<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "3x = 5 tons<BR>\n" );
document.write( "x = 5/3 tons)<BR>\n" );
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document.write( "Gravel = 5x = 5(5/3) = 25/3 = 8 1/3 tons<BR>\n" );
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document.write( "Sand = 7x = 7(5/3) = 35/3 = 11 2/3 tons<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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