document.write( "Question 836283: For what value(s) of k will the equation kx^2+(k+1)x-1=0 have exactly one solution?
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Algebra.Com's Answer #504074 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
ax^2 + bx + c = 0 will only have one solution if and only if the discriminant D is 0, so D = 0\r
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\n" ); document.write( "\n" ); document.write( "D = b^2 - 4ac\r
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\n" ); document.write( "\n" ); document.write( "0 = b^2 - 4ac\r
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\n" ); document.write( "\n" ); document.write( "0 = (k+1)^2 - 4(k)(-1)\r
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\n" ); document.write( "\n" ); document.write( "0 = (k+1)^2 + 4k\r
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\n" ); document.write( "\n" ); document.write( "0 = k^2 + 2k + 1 + 4k\r
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\n" ); document.write( "\n" ); document.write( "0 = k^2 + 6k + 1\r
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\n" ); document.write( "\n" ); document.write( "k^2 + 6k + 1 = 0\r
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\n" ); document.write( "\n" ); document.write( "Now use the quadratic formula to solve for k\r
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Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for k:

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\n" ); document.write( " Starting with the general quadratic
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\n" ); document.write( " \"ak%5E2%2Bbk%2Bc=0\"
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\n" ); document.write( " the general solution using the quadratic equation is:
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\n" ); document.write( " \"k+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"
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\n" ); document.write( " So lets solve \"k%5E2%2B6%2Ak%2B1=0\" ( notice \"a=1\", \"b=6\", and \"c=1\")
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\n" ); document.write( " \"k+=+%28-6+%2B-+sqrt%28+%286%29%5E2-4%2A1%2A1+%29%29%2F%282%2A1%29\" Plug in a=1, b=6, and c=1
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\n" ); document.write( " \"k+=+%28-6+%2B-+sqrt%28+36-4%2A1%2A1+%29%29%2F%282%2A1%29\" Square 6 to get 36
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\n" ); document.write( " \"k+=+%28-6+%2B-+sqrt%28+36%2B-4+%29%29%2F%282%2A1%29\" Multiply \"-4%2A1%2A1\" to get \"-4\"
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\n" ); document.write( " \"k+=+%28-6+%2B-+sqrt%28+32+%29%29%2F%282%2A1%29\" Combine like terms in the radicand (everything under the square root)
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\n" ); document.write( " \"k+=+%28-6+%2B-+4%2Asqrt%282%29%29%2F%282%2A1%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
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\n" ); document.write( " \"k+=+%28-6+%2B-+4%2Asqrt%282%29%29%2F2\" Multiply 2 and 1 to get 2
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\n" ); document.write( " So now the expression breaks down into two parts
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\n" ); document.write( " \"k+=+%28-6+%2B+4%2Asqrt%282%29%29%2F2\" or \"k+=+%28-6+-+4%2Asqrt%282%29%29%2F2\"
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\n" ); document.write( " Now break up the fraction
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\n" ); document.write( " \"k=-6%2F2%2B4%2Asqrt%282%29%2F2\" or \"k=-6%2F2-4%2Asqrt%282%29%2F2\"
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\n" ); document.write( " Simplify
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\n" ); document.write( " \"k=-3%2B2%2Asqrt%282%29\" or \"k=-3-2%2Asqrt%282%29\"
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\n" ); document.write( " So the solutions are:
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\n" ); document.write( " \"k=-3%2B2%2Asqrt%282%29\" or \"k=-3-2%2Asqrt%282%29\"
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\n" ); document.write( "\n" ); document.write( "Final Answer: \r
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\n" ); document.write( "\n" ); document.write( "The two solutions are \"k+=+-3%2B2%2Asqrt%282%29\" or \"k+=+-3-2%2Asqrt%282%29\"
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