Algebra.Com's Answer #504074 by jim_thompson5910(35256)  You can put this solution on YOUR website! ax^2 + bx + c = 0 will only have one solution if and only if the discriminant D is 0, so D = 0\r \n" );
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document.write( "D = b^2 - 4ac\r \n" );
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document.write( "0 = b^2 - 4ac\r \n" );
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document.write( "0 = (k+1)^2 - 4(k)(-1)\r \n" );
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document.write( "0 = (k+1)^2 + 4k\r \n" );
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document.write( "0 = k^2 + 2k + 1 + 4k\r \n" );
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document.write( "0 = k^2 + 6k + 1\r \n" );
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document.write( "k^2 + 6k + 1 = 0\r \n" );
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document.write( "Now use the quadratic formula to solve for k\r \n" );
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document.write( " Solved by pluggable solver: Quadratic Formula | \n" );
document.write( "Let's use the quadratic formula to solve for k:
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document.write( " Starting with the general quadratic \n" );
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document.write( " the general solution using the quadratic equation is: \n" );
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document.write( " So lets solve ( notice , , and ) \n" );
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document.write( " Plug in a=1, b=6, and c=1 \n" );
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document.write( " Square 6 to get 36 \n" );
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document.write( " Multiply to get  \n" );
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document.write( " Combine like terms in the radicand (everything under the square root) \n" );
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document.write( " Simplify the square root (note: If you need help with simplifying the square root, check out this solver) \n" );
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document.write( " Multiply 2 and 1 to get 2 \n" );
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document.write( " So now the expression breaks down into two parts \n" );
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document.write( " or  \n" );
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document.write( " Now break up the fraction \n" );
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document.write( " or  \n" );
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document.write( " Simplify \n" );
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document.write( " or  \n" );
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document.write( " So the solutions are: \n" );
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document.write( " or  \n" );
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document.write( "========================================================================= \n" );
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document.write( "Final Answer: \r \n" );
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document.write( "The two solutions are or \n" );
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