document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=836285>Question 836285</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, can you help me with my homework? \r<BR>\n" );
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document.write( "Here --> If the measure of a side of a square is decreased by 5cm, its perimeter is 28cm. \r<BR>\n" );
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document.write( "Thanks in advance :D </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #504070 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=504070\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = side length of original square\r<BR>\n" );
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document.write( "Decrease it by 5 to get x-5\r<BR>\n" );
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document.write( "Plug this into the perimeter of a square formula\r<BR>\n" );
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document.write( "P = 4s\r<BR>\n" );
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document.write( "P = 4(x-5)\r<BR>\n" );
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document.write( "28 = 4(x-5) ... plug in the given perimeter too\r<BR>\n" );
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document.write( "Now solve for x\r<BR>\n" );
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document.write( "28 = 4(x-5)\r<BR>\n" );
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document.write( "28/4 = x-5\r<BR>\n" );
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document.write( "7 = x-5\r<BR>\n" );
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document.write( "7+5 = x\r<BR>\n" );
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document.write( "12 = x\r<BR>\n" );
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document.write( "x = 12\r<BR>\n" );
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document.write( "The original side length is 12 cm\r<BR>\n" );
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document.write( "The area of the original square is 12^2 = 144 square cm\r<BR>\n" );
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document.write( "The perimeter of the original square is 4*12 = 48 cm </SPAN>\n" );
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