document.write( "Question 836249: a 30 lb bag of cement contains 35% cement and 65% sand. how much pure cement must be added to produce a cement mix that is 50% cement?
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document.write( "i started to make a chart to help visualize, but i don't know where to plug in any of the values \n" );
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Algebra.Com's Answer #504041 by LinnW(1048)![]() ![]() You can put this solution on YOUR website! Amount__|% as decimal|Total Pure \n" ); document.write( "-------------------------------- \n" ); document.write( "__30____|__0.35______|_0.35(30) \n" ); document.write( "__X_____|__1.00______|_1.00(X) \n" ); document.write( "================================ \n" ); document.write( "_(30+X)__|__0.50______|_0.50(30+X)\r \n" ); document.write( "\n" ); document.write( "(30+X) is the amount of product of the new mix \n" ); document.write( "The total pure cement for our mix is \n" ); document.write( "equal to 0.35(30) + 1.00(X). \n" ); document.write( "The 0.35(30) is the amount of pure cement \n" ); document.write( "in the original bag. \n" ); document.write( "1.00 or 100% of the unknown X amount of cement \n" ); document.write( "is represented by 1.00(X) \n" ); document.write( "These two quantities together need to add \n" ); document.write( "up the new 50% mix represented by 0.50(30+X) \n" ); document.write( "So 0.35(30) + 1.00(X) = 0.50(30+X) \n" ); document.write( "10.50 + X = 15 + 0.5X \n" ); document.write( "add -0.5X to each side \n" ); document.write( "10.50 + 0.5X = 15 \n" ); document.write( "add -10.50 to each side \n" ); document.write( "0.5X = 4.50 \n" ); document.write( "X = 9 \n" ); document.write( "Our new mix is a total of 39 pounds. \n" ); document.write( "The amount of pure cement in the new mix is 35% of 30 + 9 or \n" ); document.write( "10.50 + 9 , 19.5 pounds of cement. \n" ); document.write( "Since the new mix weighs 39 pounds, clearly 50% is cement. \n" ); document.write( " \n" ); document.write( " |