document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=836205>Question 836205</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a collection of 10 nickels and dimes is worth $0.80. Find the number of nickels and dimes.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #504038 by </B><A HREF=/tutors/aboutme.mpl?userid=LinnW><B>LinnW(1048)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LinnW><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=LinnW><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=504038\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> n = no of nickles<BR>\n" );
document.write( "d = no of dimes<BR>\n" );
document.write( "n + d = 10<BR>\n" );
document.write( "add -d to each side<BR>\n" );
document.write( "n = 10 - d<BR>\n" );
document.write( "n(5) + d(10) = 80 cents<BR>\n" );
document.write( "substitute (10 - d) for n<BR>\n" );
document.write( "(10 - d)(5) + d(10) = 80<BR>\n" );
document.write( "50 - 5d + 10d = 80<BR>\n" );
document.write( "50 + 5d = 80<BR>\n" );
document.write( "add -50 to each side<BR>\n" );
document.write( "5d = 30<BR>\n" );
document.write( "d = 6<BR>\n" );
document.write( "Since there are 10 coins all together n = 4<BR>\n" );
document.write( "60 cents is dimes and 20 cents in nickles </SPAN>\n" );
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