document.write( "Question 836225: Classify the polygon if the sum of the exterior angles is twice the sum of the interior angles. I know the polygon is a triangle, but how do I set up the equation to find the answer? \n" ); document.write( "
Algebra.Com's Answer #504037 by Edwin McCravy(20059)\"\" \"About 
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document.write( "The sum of the interior angles of an n-sided polygon is given by the\r\n" );
document.write( "formula (n-2)·180°.\r\n" );
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document.write( "The sum of the exterior angles of ANY polygon is 360°.\r\n" );
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document.write( "We are told that the sum of the exterior angles is twice the sum of the interior angles:\r\n" );
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document.write( "360° = 2[(n-2)180°]\r\n" );
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document.write( "360 = 360(n-2)\r\n" );
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document.write( "Divide both sides by 360\r\n" );
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document.write( "1 = n-2\r\n" );
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document.write( "Add 2 to both sides\r\n" );
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document.write( "3 = n\r\n" );
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document.write( "Edwin
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