document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=836217>Question 836217</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ray is 3 more than twice the age of his sister, Becky. Combined their ages sum to 27. Find both Ray's age and Becky's age. Please show work!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #504036 by </B><A HREF=/tutors/aboutme.mpl?userid=LinnW><B>LinnW(1048)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LinnW><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=LinnW><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=504036\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> R = Ray's age<BR>\n" );
document.write( "B = Becky's age<BR>\n" );
document.write( "R = 2B + 3<BR>\n" );
document.write( "R + B = 27<BR>\n" );
document.write( "Substitute (2B + 3) for R in R + B = 27<BR>\n" );
document.write( "(2B + 3) + B = 27<BR>\n" );
document.write( "3B + 3 = 27<BR>\n" );
document.write( "add -3 to each side<BR>\n" );
document.write( "3B = 24<BR>\n" );
document.write( "divide by 3<BR>\n" );
document.write( "B = 8<BR>\n" );
document.write( "Since R = 2B + 3<BR>\n" );
document.write( "R = 2(8) + 3<BR>\n" );
document.write( "R = 16 + 3<BR>\n" );
document.write( "R = 19 </SPAN>\n" );
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