document.write( "Question 836115: if 5 digits number
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document.write( "is formed using odd digits without
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document.write( "repetition,what is the sum of the all
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document.write( "possible number? . \n" );
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Algebra.Com's Answer #503980 by KMST(5328)![]() ![]() You can put this solution on YOUR website! There are many ways to get to the answer. \n" ); document.write( "I listed the one that seemed easier for my own mind to understand and calculate. \n" ); document.write( "With some luck, it might sound logical and understandable for you too. \n" ); document.write( " \n" ); document.write( "There are 5 odd digits: 1, 3, 5, 7, and 9. \n" ); document.write( " \n" ); document.write( "How many 5-digit numbers can we make using those digits without repetition? \n" ); document.write( "We have 5 ways to choose the first digit. \n" ); document.write( "For each of those choices, there will be 4 ways to chose the second digit. \n" ); document.write( "For each set of first and second digit choices, there will be 3 ways to chose the third digit. \n" ); document.write( "For each set of first, second and third digit choices, there will be 2 ways to chose the fourth digit. \n" ); document.write( "all in all, there are \n" ); document.write( " \n" ); document.write( "All 5 of those 5 odd digits are equally likely as the last (units) digit. \n" ); document.write( "The last digit will be a 1 in \n" ); document.write( "The last digit will be a 3 in another 24 numbers, a 5 in another 24, a 7 in another 24, and a 9 in another 24 numbers. \n" ); document.write( "All the last digits added up will add up to \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The sum of the tens digits will also be \n" ); document.write( "and so will be the sums of the hundreds, thousands, and ten-thousands digits. \n" ); document.write( " \n" ); document.write( "The value of the sum of all the numbers will be \n" ); document.write( " |